2.2
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Your book says the word comes from the Greek logos and arithmos, meaning ratio or proportion. The Scottish mathematician John Napier introduced it to simplify multiplying and dividing large numbers.
The logarithm of x to the base b is y, written log_b x = y. It means b raised to the power y equals x: bʸ = x.
In that statement b is the base, x is the result and y is the exponent. The base must be positive and not 1, and x must be positive.
Every log statement can be rewritten as a power, and back. That switch solves most of the questions in this section.
log28 = 3 ⇔ 23 = 8
log10100 = 2 ⇔ 102 = 100
34 = 81 ⇔ log381 = 4
70 = 1 ⇔ log71 = 0
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Your book says the word comes from the Greek logos and arithmos, meaning ratio or proportion. The Scottish mathematician John Napier introduced it to simplify multiplying and dividing large numbers.
The logarithm of x to the base b is y, written log_b x = y. It means b raised to the power y equals x: bʸ = x.
In that statement b is the base, x is the result and y is the exponent. The base must be positive and not 1, and x must be positive.
Every log statement can be rewritten as a power, and back. That switch solves most of the questions in this section.
log28 = 3 ⇔ 23 = 8
log10100 = 2 ⇔ 102 = 100
34 = 81 ⇔ log381 = 4
70 = 1 ⇔ log71 = 0
Read log_b x as: what power of b gives x? The answer to that question is the logarithm.
Q1. Example 7 (i): find x if log525 = x.
x = 2.
Q2. Example 8: write 34 = 81 and 70 = 1 in logarithmic form.
log381 = 4 and log71 = 0.
✗ Writing 34 = 81 as log481 = 3.
✓ The base of the power is the base of the log: log381 = 4.
✗ Reading log2x = 6 as x = 2 × 6 = 12.
✓ A log gives a power, not a product: x = 26 = 64.
✗ Writing log 0 = 0.
✓ x must be positive; no power of b gives 0, so log 0 is undefined.
1. 34 = 81 in logarithmic form is:
(c) Base 3, power 4 (Review Exercise 2 x).
2. log28 = 3 in exponential form is:
(a) Example 5, p. 23.
3. If log2x = 6, then x =
(d) x = 26 = 64 (Example 7 ii).
4. log223 equals:
(b) 2 to the power 3 gives 23, so the log is 3 (Review Exercise 2 iv).
5. Which condition does your book put on the base b?
(a) b > 0, x > 0 and b ≠ 1 (p. 23).
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