2.4
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Your book gives four laws that simplify log expressions and solve log equations. Each one comes straight from a law of indices.
Product law: log_b xy = log_b x + log_b y. Quotient law: log_b (x/y) = log_b x − log_b y. The log of a product is a sum; of a quotient, a difference.
Power law: log_b xⁿ = n log_b x, so a power comes down in front. Change of base: log_b x = log_a x / log_a b, which lets you use any base.
The proofs all start the same way: let m = log_b x and n = log_b y, so x = bᵐ and y = bⁿ. Then xy = b^(m+n) gives the product law.
log320 = log3(22 × 5) = 2 log32 + log35
log295 = log2310 = 10 log23
log3227 = log 33 / log 25 = (3/5) log23
6 log3x + 2 log311 = log3(121x6)
Step 1 / 7
Your book gives four laws that simplify log expressions and solve log equations. Each one comes straight from a law of indices.
Product law: log_b xy = log_b x + log_b y. Quotient law: log_b (x/y) = log_b x − log_b y. The log of a product is a sum; of a quotient, a difference.
Power law: log_b xⁿ = n log_b x, so a power comes down in front. Change of base: log_b x = log_a x / log_a b, which lets you use any base.
The proofs all start the same way: let m = log_b x and n = log_b y, so x = bᵐ and y = bⁿ. Then xy = b^(m+n) gives the product law.
log320 = log3(22 × 5) = 2 log32 + log35
log295 = log2310 = 10 log23
log3227 = log 33 / log 25 = (3/5) log23
6 log3x + 2 log311 = log3(121x6)
To expand: break products and quotients apart, then bring powers down. To combine: lift numbers in front up as powers first, then join.
Q1. Example 13 (ii): expand log5(xy/z)8.
8[log5x + log5y − log5z].
Q2. Example 15: L = 40 log10(I/I0) as printed in your book. Find L when I = 106 I0.
240 decibels, as your book says. Teacher note: the usual formula has 10, not 40, which gives 60 dB.
✗ log 5 + log 3 = log 8.
✓ A sum of logs is the log of a product: log 15.
✗ 2 log310 − log34 = log3(10/4) × 2.
✓ First lift the 2 up as a power: log3102 = log3100, then divide: log325.
✗ log x / log y = log x − log y.
✓ The quotient law is about log (x/y), not a fraction of two logs; log x / log y is change of base.
1. log 5 + log 3 =
(a) Product law (Review Exercise 2 ix).
2. log295 expands to:
(c) 95 = 310 (Example 12 ii).
3. 6 log3x + 2 log311 as a single log is:
(d) Powers up, then product law (Example 14 ii).
4. M = log10(A/A0) with A = 10,000 and A0 = 10 gives M =
(b) 10,000/10 = 1000 = 103 (Exercise 2.4 Q6).
5. log3227 by change of base is:
(c) log 33 / log 25 = (3/5) log23 (Example 12 iii).
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