2.3.3
Your guide: Sir AhmedSays brackets have saved more marks than any calculator.
An antilogarithm is the inverse of a logarithm. If log_b x = y, finding x is called taking the antilogarithm of y.
In 45 = 1024, the base is 4, the logarithm is 5 and the antilogarithm is 1024. The antilogarithm is just the number, or result.
With tables: split the log into characteristic and mantissa. Look up the mantissa in the antilog table and add the mean difference.
Then place the point using the characteristic. Count from the reference position, between the first non-zero digit and the next: right for a positive characteristic, left for a barred one.
Characteristic 2, mantissa 0.1245
Row .12, column 4 â 1330; mean difference column 5 â 2
1332 â point 2 digits right of 1 â 133.2
Step 1 / 7
An antilogarithm is the inverse of a logarithm. If log_b x = y, finding x is called taking the antilogarithm of y.
In 45 = 1024, the base is 4, the logarithm is 5 and the antilogarithm is 1024. The antilogarithm is just the number, or result.
With tables: split the log into characteristic and mantissa. Look up the mantissa in the antilog table and add the mean difference.
Then place the point using the characteristic. Count from the reference position, between the first non-zero digit and the next: right for a positive characteristic, left for a barred one.
Characteristic 2, mantissa 0.1245
Row .12, column 4 â 1330; mean difference column 5 â 2
1332 â point 2 digits right of 1 â 133.2
A negative log must first be made into a barred characteristic plus a positive mantissa: â1.4567 = 2Ě.5433.
Q1. Example 11 (ii): find x if log x = â1.4567.
x = 0.03493.
Q2. Example 11 (iii): find x if log x = â2.1234.
x = 0.007526.
â Looking up 0.4567 in the table for log x = â1.4567.
â First rewrite as 2Ě.5433; look up 0.5433.
â Counting places from the start of 1332: 13.32.
â Count from the reference position after the 1: 133.2.
â Using the log table to find an antilog.
â Antilogs need the antilog table, with rows .00 to .99.
1. In 43 = 64, the antilogarithm is:
(d) The result is the antilogarithm (p. 28).
2. antilog 2.1245 =
(b) Characteristic 2: two places right of the 1 (p. 28).
3. â1.4567 written with a positive mantissa is:
(a) â2 + 0.5433 (Example 11 ii).
4. If log x = 0.2568, then x is:
(c) Characteristic 0: point right at the reference position (Example 11 i).
5. If log x = 3Ě.8766, then x is:
(b) Three places left of the reference position (Example 11 iii).
Found a mistake? Tell us the lesson and the line at exciting@boringeducation.com.
Free right now. No ads. Tell us what to fix.