1.2.2Free
Your guide: Sir AhmedSays brackets have saved more marks than any calculator.
A surd is an irrational radical with a rational radicand. √5 is a surd because no whole number squares to 5. √9 is not, since it simplifies to 3.
√π and √e are irrational but not surds, because π and e are not rational. Your book: every surd is irrational, but not every irrational number is a surd.
A monomial surd has one term, like √5. A binomial surd is a sum of two, like √3 + √5. √a + √b and √a − √b are conjugates, and their product is rational.
To rationalize a denominator, multiply top and bottom by its conjugate. The bottom becomes (√a)2 − (√b)2 = a − b, with no root left.
3/(√5 + √2) × (√5 − √2)/(√5 − √2) = 3(√5 − √2)/(5 − 2) = √5 − √2
3/(√5 − √3) × (√5 + √3)/(√5 + √3) = 3(√5 + √3)/(5 − 3) = 3(√5 + √3)/2
Step 1 / 7
A surd is an irrational radical with a rational radicand. √5 is a surd because no whole number squares to 5. √9 is not, since it simplifies to 3.
√π and √e are irrational but not surds, because π and e are not rational. Your book: every surd is irrational, but not every irrational number is a surd.
A monomial surd has one term, like √5. A binomial surd is a sum of two, like √3 + √5. √a + √b and √a − √b are conjugates, and their product is rational.
To rationalize a denominator, multiply top and bottom by its conjugate. The bottom becomes (√a)2 − (√b)2 = a − b, with no root left.
3/(√5 + √2) × (√5 − √2)/(√5 − √2) = 3(√5 − √2)/(5 − 2) = √5 − √2
3/(√5 − √3) × (√5 + √3)/(√5 + √3) = 3(√5 + √3)/(5 − 3) = 3(√5 + √3)/2
Change only the sign between the two terms to get the conjugate. Then (√a + √b)(√a − √b) = a − b.
Q1. Example 8 (ii): rationalize 3/(√5 − √3).
3(√5 + √3)/2.
Q2. Is √9 a surd? Is √π?
Neither is a surd (p. 12).
✗ Multiplying only the denominator by the conjugate.
✓ Multiply top and bottom, so the value stays the same.
✗ Using √5 + √2 itself to rationalize 3/(√5 + √2).
✓ (√5 + √2)2 = 7 + 2√10 still has a root. Use √5 − √2.
✗ Calling √π a surd because it is irrational.
✓ The radicand π is not rational, so √π is not a surd (p. 12).
1. Which one is a surd?
(c) 7 is rational and √7 is irrational (p. 12).
2. The conjugate of √5 − √3 is:
(a) Change only the middle sign (p. 13).
3. (√5 + √2)(√5 − √2) =
(c) 5 − 2 = 3, a rational number.
4. 3/(√5 − √3) rationalized is:
(d) 5 − 3 = 2 stays in the bottom (Example 8 ii).
5. (3 + √5)(3 − √5) is:
(b) 9 − 5 = 4; conjugates multiply to a rational (Review Exercise 1 x).
Found a mistake? Tell us the lesson and the line at exciting@boringeducation.com.
Free right now. No ads. Tell us what to fix.