BORING EDUCATION — LIVE EXPERIMENTProduct is live. Experiments are running. Feedback is being collected. Improvements are underway.Welcome to Boring Education. We're glad you're here while we're figuring out how to make learning better.
BORINGEDUCATION

1.2.2Free

Surds and rationalizing the denominator

Your guide: Sir AhmedSays brackets have saved more marks than any calculator.

Roots that never come out

A surd is an irrational radical with a rational radicand. √5 is a surd because no whole number squares to 5. √9 is not, since it simplifies to 3.

√π and √e are irrational but not surds, because π and e are not rational. Your book: every surd is irrational, but not every irrational number is a surd.

A monomial surd has one term, like √5. A binomial surd is a sum of two, like √3 + √5. √a + √b and √a − √b are conjugates, and their product is rational.

To rationalize a denominator, multiply top and bottom by its conjugate. The bottom becomes (√a)2 − (√b)2 = a − b, with no root left.

Example 8 (p. 13)

3/(√5 + √2) × (√5 − √2)/(√5 − √2) = 3(√5 − √2)/(5 − 2) = √5 − √2

3/(√5 − √3) × (√5 + √3)/(√5 + √3) = 3(√5 + √3)/(5 − 3) = 3(√5 + √3)/2

Change only the sign between the two terms to get the conjugate. Then (√a + √b)(√a − √b) = a − b.

Step 1 / 7

Notes, short questions and MCQs

Read the full notes: key terms, model answers and MCQs with answers

Roots that never come out

A surd is an irrational radical with a rational radicand. √5 is a surd because no whole number squares to 5. √9 is not, since it simplifies to 3.

√π and √e are irrational but not surds, because π and e are not rational. Your book: every surd is irrational, but not every irrational number is a surd.

A monomial surd has one term, like √5. A binomial surd is a sum of two, like √3 + √5. √a + √b and √a − √b are conjugates, and their product is rational.

To rationalize a denominator, multiply top and bottom by its conjugate. The bottom becomes (√a)2 − (√b)2 = a − b, with no root left.

Example 8 (p. 13)

3/(√5 + √2) × (√5 − √2)/(√5 − √2) = 3(√5 − √2)/(5 − 2) = √5 − √2

3/(√5 − √3) × (√5 + √3)/(√5 + √3) = 3(√5 + √3)/(5 − 3) = 3(√5 + √3)/2

Change only the sign between the two terms to get the conjugate. Then (√a + √b)(√a − √b) = a − b.

Key terms

Surd
Roots that stay as roots.
Binomial surd
A sum of two monomial surds.
Conjugate surds
Their product has no root.
Rationalization
Clearing roots from a denominator.

Short questions with model answers

  1. Q1. Example 8 (ii): rationalize 3/(√5 − √3).

    • 3/(√5 − √3) × (√5 + √3)/(√5 + √3)
    • 3(√5 + √3)/((√5)2 − (√3)2) = 3(√5 + √3)/(5 − 3)

    3(√5 + √3)/2.

  2. Q2. Is √9 a surd? Is √π?

    • √9 = 3
    • π is not rational

    Neither is a surd (p. 12).

Common mistakes

  • ✗ Multiplying only the denominator by the conjugate.

    ✓ Multiply top and bottom, so the value stays the same.

  • ✗ Using √5 + √2 itself to rationalize 3/(√5 + √2).

    ✓ (√5 + √2)2 = 7 + 2√10 still has a root. Use √5 − √2.

  • ✗ Calling √π a surd because it is irrational.

    ✓ The radicand π is not rational, so √π is not a surd (p. 12).

MCQs

  1. 1. Which one is a surd?

    1. (a) √9
    2. (b) √π
    3. (c) √7
    4. (d) √e
    Show answer

    (c) 7 is rational and √7 is irrational (p. 12).

  2. 2. The conjugate of √5 − √3 is:

    1. (a) √5 + √3
    2. (b) √3 − √5
    3. (c) −√5 − √3
    4. (d) √5 − √3
    Show answer

    (a) Change only the middle sign (p. 13).

  3. 3. (√5 + √2)(√5 − √2) =

    1. (a) 7
    2. (b) √3
    3. (c) 3
    4. (d) 10
    Show answer

    (c) 5 − 2 = 3, a rational number.

  4. 4. 3/(√5 − √3) rationalized is:

    1. (a) √5 + √3
    2. (b) 3(√5 − √3)/2
    3. (c) (√5 + √3)/2
    4. (d) 3(√5 + √3)/2
    Show answer

    (d) 5 − 3 = 2 stays in the bottom (Example 8 ii).

  5. 5. (3 + √5)(3 − √5) is:

    1. (a) an irrational number
    2. (b) a rational number
    3. (c) a surd
    4. (d) undefined
    Show answer

    (b) 9 − 5 = 4; conjugates multiply to a rational (Review Exercise 1 x).

Quick revision

  • A surd is an irrational root of a rational number; √π is not one.
  • Conjugates √a ± √b multiply to a − b, a rational number.
  • Rationalize by multiplying top and bottom by the conjugate.

Before you start

What is Class 9 Maths Surds and rationalization of the denominator?
Surds and rationalization of the denominator is the open Class 9 Maths lesson for Matric Part 1, Punjab board. It is a step-by-step lesson, not a PDF of the book.
Which boards is this Class 9 Maths lesson for?
The same Punjab textbook: Lahore, Rawalpindi, Gujranwala, Faisalabad, Multan, Sargodha, Bahawalpur, Dera Ghazi Khan, Sahiwal.
Can I study this in Urdu?
Yes. English, Urdu or Roman Urdu. Science terms stay as the exam writes them.
Is this a notes PDF?
No. The book stays with you. This page is the lesson and the check.

Found a mistake? Tell us the lesson and the line at exciting@boringeducation.com.

Free right now. No ads. Tell us what to fix.