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You already place fractions on a number line. Irrational numbers need a construction, because you cannot count out their decimal places.
To place â5: mark OA = 2 units from O, draw AB = 1 unit upright at A. Pythagoras gives OB2 = 22 + 12 = 5, so OB = â5.
With centre O and radius OB, draw an arc down to the line. It meets the line at P, and |OP| = â5 â 2.236.
A recurring decimal can be turned back into p/q. Let x be the decimal, multiply by 10 or 100 to shift one block, then subtract.
OB2 = 22 + 12 = 4 + 1 = 5 â |OP| = â5
0.5Ě: 10x â x = 5 â x = 5/9
0.93Ě: 100x â x = 93 â x = 93/99
Between 2 and 3: 5/2 and 11/4
Step 1 / 7
You already place fractions on a number line. Irrational numbers need a construction, because you cannot count out their decimal places.
To place â5: mark OA = 2 units from O, draw AB = 1 unit upright at A. Pythagoras gives OB2 = 22 + 12 = 5, so OB = â5.
With centre O and radius OB, draw an arc down to the line. It meets the line at P, and |OP| = â5 â 2.236.
A recurring decimal can be turned back into p/q. Let x be the decimal, multiply by 10 or 100 to shift one block, then subtract.
OB2 = 22 + 12 = 4 + 1 = 5 â |OP| = â5
0.5Ě: 10x â x = 5 â x = 5/9
0.93Ě: 100x â x = 93 â x = 93/99
Between 2 and 3: 5/2 and 11/4
Multiply by 10 when one digit repeats and by 100 when two digits repeat. The repeating tails then cancel.
Q1. Example 3 (i): express 0.5Ě as p/q.
0.5Ě = 5/9.
Q2. Example 4: find two rational numbers between 2 and 3.
5/2 and 11/4.
â Multiplying 0.93Ě by 10.
â Two digits repeat, so use 100; then 100x â x = 93.
â Writing 0.5Ě = 5/10.
â 5/10 = 0.5 stops. The recurring one is 5/9.
â Drawing the arc with centre A instead of O.
â The length â5 is OB, measured from O, so the arc's centre is O.
1. In Example 2, OA = 2 and AB = 1. Then OB2 is:
(b) 22 + 12 = 4 + 1 = 5 (p. 5).
2. 0.5Ě as p/q is:
(c) 9x = 5, so x = 5/9 (p. 6).
3. To convert 0.93Ě, multiply x by:
(a) Two digits repeat (p. 6).
4. Which is a rational number between 2 and 3 from Example 4?
(d) (5/2 + 3)/2 = 11/4 (p. 6).
5. By your book's Remember box, 2 + â5 is:
(c) Rational + irrational = irrational (p. 5).
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