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If n is a positive integer greater than 1, any real x with x = ⁿ√a is the nth root of a. The sign √ is the radical, n is its index and a is the radicand.
Your book writes every root as a power: ⁿ√a = a^(1/n). Once a root is a power, the laws of indices do all the work.
Multiply powers of the same base: add the indices. Divide: subtract them. A power of a power: multiply them. Anything (non-zero) to the power 0 is 1.
ⁿ√(ab) = ⁿ√a · ⁿ√b
ⁿ√(a/b) = ⁿ√a / ⁿ√b
ⁿ√(aᵐ) = (ⁿ√a)ᵐ; (ⁿ√a)ⁿ = a
aᵐ · aⁿ = a^(m+n); aᵐ / aⁿ = a^(m−n)
(aᵐ)ⁿ = a^(mn); (ab)ⁿ = aⁿbⁿ
(a/b)ⁿ = aⁿ/bⁿ; a0 = 1
Step 1 / 7
If n is a positive integer greater than 1, any real x with x = ⁿ√a is the nth root of a. The sign √ is the radical, n is its index and a is the radicand.
Your book writes every root as a power: ⁿ√a = a^(1/n). Once a root is a power, the laws of indices do all the work.
Multiply powers of the same base: add the indices. Divide: subtract them. A power of a power: multiply them. Anything (non-zero) to the power 0 is 1.
ⁿ√(ab) = ⁿ√a · ⁿ√b
ⁿ√(a/b) = ⁿ√a / ⁿ√b
ⁿ√(aᵐ) = (ⁿ√a)ᵐ; (ⁿ√a)ⁿ = a
aᵐ · aⁿ = a^(m+n); aᵐ / aⁿ = a^(m−n)
(aᵐ)ⁿ = a^(mn); (ab)ⁿ = aⁿbⁿ
(a/b)ⁿ = aⁿ/bⁿ; a0 = 1
Turn the root into a power, split the product, then multiply the indices. That is the whole of Example 7.
Q1. Example 7 (i): simplify 4√(16x4y8).
2xy2.
Q2. Example 7 (ii): simplify ∛(27x6y9z3).
3x2y3z.
✗ Writing (x4)^(1/4) = x^(4 + 1/4).
✓ A power of a power multiplies: x^(4 × 1/4) = x.
✗ Treating (64)^(−4/3) as a negative number.
✓ A negative index means a reciprocal: a^(−m) = 1/aᵐ, so the answer is 1/256.
✗ Leaving 16 outside the fourth root: 4√(16x4y8) = 16xy2.
✓ The root acts on every factor: 4√16 = 2.
1. In ∛5, the index is:
(c) n = 3 is the index; 5 is the radicand (p. 11).
2. 4√(16x4y8) =
(a) Example 7 (i), p. 12.
3. (64)^(−4/3) =
(d) 1/(43)^(4/3) = 1/44 = 1/256 (p. 12).
4. aᵐ / aⁿ equals:
(b) Dividing subtracts the indices (p. 11).
5. If 2ˣ × 8ˣ = 64, then x =
(a) 2ˣ·23ˣ = 24ˣ = 26, so 4x = 6, x = 3/2 (Review Exercise 1 vii).
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