4.2
Your guide: Miss SanaCounts atoms the way you count rupees: carefully.
The empirical formula gives the simplest whole-number ratio of the atoms in a compound. It tells you the ratio, not the real number of atoms in a molecule.
To find it, divide every subscript by their highest common factor. H2O2 divides by 2 to give HO. C6H6 divides by 6 to give CH. Glucose C6H12O6 (p. 56) gives CH2O.
Sometimes nothing divides: H2O, CH4 and NH3 already show the simplest ratio, so their empirical and molecular formulas are the same.
Ionic compounds have no molecules, so their formula unit is already the empirical formula: NaCl, CaF2, MgO, CaCO3.
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The empirical formula gives the simplest whole-number ratio of the atoms in a compound. It tells you the ratio, not the real number of atoms in a molecule.
To find it, divide every subscript by their highest common factor. H2O2 divides by 2 to give HO. C6H6 divides by 6 to give CH. Glucose C6H12O6 (p. 56) gives CH2O.
Sometimes nothing divides: H2O, CH4 and NH3 already show the simplest ratio, so their empirical and molecular formulas are the same.
Ionic compounds have no molecules, so their formula unit is already the empirical formula: NaCl, CaF2, MgO, CaCO3.
Two different compounds can share one empirical formula: benzene C6H6 and acetylene C2H2 are both CH.
Q1. Find the empirical formula of benzene, C6H6. (p. 54)
Empirical formula CH.
Q2. Find the empirical formula of NH3.
Empirical formula NH3, the same as its molecular formula.
✗ HO is the formula of a real hydrogen peroxide molecule.
✓ HO is only the ratio; the molecule is H2O2.
✗ Empirical and molecular formulas are always different.
✓ For H2O, CH4 and NH3 they are the same.
✗ C6H12O6 simplifies to C3H6O3.
✓ Divide by the highest common factor, 6: CH2O.
1. The empirical formula of H2O2 is:
(b) Divide both subscripts by 2 (p. 54).
2. Which compound has the same empirical and molecular formula?
(c) 1 : 4 cannot be reduced.
3. Glucose C6H12O6 has the empirical formula:
(d) Divide by 6 (glucose, p. 56).
4. Benzene and acetylene share the empirical formula:
(a) C6H6 and C2H2 both reduce to 1 : 1.
5. For calcium fluoride, the empirical formula is:
(c) For ionic compounds the formula unit is the empirical formula (p. 53).
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