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|−5| = 5 tells you how far −5 is from 0 on the number line. A complex number sits on a plane, so its distance from the origin is the slanted side of a right triangle.
The two short sides are x and y (Fig. 1.13). Pythagoras gives the distance: √(x2 + y2). This distance is the modulus.
If z = x + iy, then |z| = √(x2 + y2).
|i| = √(02 + 12) = 1 and |3 − 5i| = √(9 + 25) = √34.
1. |z| = |z̄|.
2. |−z| = |z| = |z̄| = |−z̄|.
3. z z̄ = |z|2.
Step 1 / 7
|−5| = 5 tells you how far −5 is from 0 on the number line. A complex number sits on a plane, so its distance from the origin is the slanted side of a right triangle.
The two short sides are x and y (Fig. 1.13). Pythagoras gives the distance: √(x2 + y2). This distance is the modulus.
If z = x + iy, then |z| = √(x2 + y2).
|i| = √(02 + 12) = 1 and |3 − 5i| = √(9 + 25) = √34.
1. |z| = |z̄|.
2. |−z| = |z| = |z̄| = |−z̄|.
3. z z̄ = |z|2.
|z| = √(x2 + y2) is the distance of z from the origin. Changing signs does not change it, and z z̄ = |z|2.
Q1. Example 15 (p. 14): z = 5 + 4i. Show |z| = |z̄|.
|z| = |z̄| = √41
Q2. Example 16 (pp. 15–16): z = 5 + 3i. Show z z̄ = |z|2.
Both are 34.
✗ |5 + 4i| = 41.
✓ 41 is |z|2. The modulus is √41.
✗ |5 + 4i| = 5 + 4 = 9.
✓ Square, add, then take the root: √(25 + 16).
✗ |3 − 5i| = √(9 − 25).
✓ Use y = −5, not −5i: y2 = 25, so √(9 + 25) = √34.
1. If z = 4 − 3i, then z z̄ =
(d) Review Q1(vii) (p. 21): 16 + 9 = 25.
2. |i| =
(b) p. 14: √(02 + 12) = 1. A modulus is never negative.
3. |4 + 3i| = (Exercise 1.3 Q1(ii))
(a) √(16 + 9) = √25 = 5.
4. |−5 − 4i| = (Exercise 1.3 Q1(iii))
(c) √(25 + 16) = √41; the signs do not matter after squaring.
5. Which is NOT always true?
(d) Properties 1–3 (pp. 14–15) hold; the modulus uses squares and a root.
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