1.1.2Free
Your guide: Sir AhmedSays brackets have saved more marks than any calculator.
With real numbers, one equation usually finds one unknown. With complex numbers, one equation can find two. The trick is that a complex number has two separate parts.
Two complex numbers are equal only when their real parts match and their imaginary parts match. So one complex equation splits into two real equations.
z1 = x1 + iy1 and z2 = x2 + iy2 are equal if and only if x1 = x2 and y1 = y2.
For example, α + iβ = −2 + 5i gives α = −2 and β = 5.
Collect each side into one real part and one imaginary part.
Set real = real and imaginary = imaginary, then solve the two equations.
Step 1 / 7
With real numbers, one equation usually finds one unknown. With complex numbers, one equation can find two. The trick is that a complex number has two separate parts.
Two complex numbers are equal only when their real parts match and their imaginary parts match. So one complex equation splits into two real equations.
z1 = x1 + iy1 and z2 = x2 + iy2 are equal if and only if x1 = x2 and y1 = y2.
For example, α + iβ = −2 + 5i gives α = −2 and β = 5.
Collect each side into one real part and one imaginary part.
Set real = real and imaginary = imaginary, then solve the two equations.
Equal complex numbers have equal real parts and equal imaginary parts. One complex equation gives two real equations.
Q1. Example 2 (p. 4): if (2x − 1) + (y + 4)i = 5 + 7i, find x and y.
x = 3, y = 3
Q2. Exercise 1.1 Q3(i) (p. 4): (2x + 5) + (y − 3)i = 1 + 2i.
x = −2, y = 5
✗ y + 4 = 7i.
✓ Compare the coefficients of i: y + 4 = 7. The parts are real numbers.
✗ In (2 + i)x + (1 − 2i)y, the real part is 2 + 1.
✓ Multiply out first. The real part is 2x + y and the imaginary part is x − 2y.
✗ (3x + 2) − (4 − y)i = 5 + 3i gives 4 − y = 3.
✓ The imaginary part is −(4 − y), so −(4 − y) = 3 and y = 7.
1. If α + iβ = −2 + 5i, then:
(c) p. 3: compare parts; β is real.
2. Two complex numbers are equal when:
(b) Review Q2(iii) (p. 21): both parts must match.
3. (3x + 2) − (4 − y)i = 5 + 3i. Find y (Exercise 1.1 Q3(ii)).
(d) −(4 − y) = 3, so y − 4 = 3 and y = 7.
4. Same equation: find x.
(a) 3x + 2 = 5, so x = 1.
5. Expand (2 + i)x + (1 − 2i)y. Its imaginary part is:
(b) The i terms are ix and −2iy.
Found a mistake? Tell us the lesson and the line at exciting@boringeducation.com.
Free right now. No ads. Tell us what to fix.