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Your guide: Sir HamzaBelieves every formula has a story, and units never lie.
Latent heat is the heat absorbed or released when a substance changes state without changing its temperature. The energy breaks or forms the bonds between molecules instead of speeding them up.
Latent heat of fusion Lf is the heat to melt 1 kg of a solid at its melting point. For ice, Lf = 3.36 × 105 J kg−1, and Q = m Lf.
Latent heat of vaporisation Lv is the heat to turn 1 kg of a liquid into vapour at its boiling point. For water, Lv = 2.26 × 106 J kg−1, and Q = m Lv.
Heat crushed ice steadily: the temperature stays at 0 °C until all the ice has melted, then rises.
Heat water to boiling: the temperature stays at 100 °C while it boils away.
The flat parts of the graph are where latent heat is being absorbed.
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Latent heat is the heat absorbed or released when a substance changes state without changing its temperature. The energy breaks or forms the bonds between molecules instead of speeding them up.
Latent heat of fusion Lf is the heat to melt 1 kg of a solid at its melting point. For ice, Lf = 3.36 × 105 J kg−1, and Q = m Lf.
Latent heat of vaporisation Lv is the heat to turn 1 kg of a liquid into vapour at its boiling point. For water, Lv = 2.26 × 106 J kg−1, and Q = m Lv.
Heat crushed ice steadily: the temperature stays at 0 °C until all the ice has melted, then rises.
Heat water to boiling: the temperature stays at 100 °C while it boils away.
The flat parts of the graph are where latent heat is being absorbed.
During melting or boiling the thermometer stops rising, but heat is still going in. It goes into breaking bonds, not into speed.
Q1. Example 10.2 (p. 13): how much heat melts 600 g (0.600 kg) of ice at 0 °C? Lf = 3.36 × 105 J kg−1.
201,600 J, about 201.6 kJ.
Q2. Numerical 10.7 (p. 18): how much heat turns 1 kg of water at 100 °C into steam? Lv = 2.26 × 106 J kg−1.
2.26 × 106 J = 2.26 MJ, the book's answer.
✗ While ice melts, its temperature keeps rising.
✓ It stays at 0 °C until all the ice has melted (Fig. 10.12).
✗ Use 500 g directly in Q = m Lf.
✓ Lf is per kilogram, so use 0.5 kg.
✗ Use Lf to boil water.
✓ Lf is for melting; Lv is for boiling, and it is much larger.
1. During melting, the supplied heat mainly:
(b) p. 13: latent heat breaks or forms intermolecular bonds.
2. The latent heat of fusion of ice is:
(d) p. 13. 2.26 × 106 J kg−1 is Lv of water.
3. Heat needed to melt 2 kg of ice at 0 °C:
(a) Q = 2 × 3.36 × 105 = 6.72 × 105 J = 672 kJ.
4. On the temperature–time graph for heating ice, the flat parts show:
(c) Fig. 10.12: latent heat is absorbed at constant temperature.
5. Which needs more energy for 1 kg of water?
(b) Lv (2.26 × 106) is almost seven times Lf (3.36 × 105).
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